3x+13=x^2+25

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Solution for 3x+13=x^2+25 equation:



3x+13=x^2+25
We move all terms to the left:
3x+13-(x^2+25)=0
We get rid of parentheses
-x^2+3x-25+13=0
We add all the numbers together, and all the variables
-1x^2+3x-12=0
a = -1; b = 3; c = -12;
Δ = b2-4ac
Δ = 32-4·(-1)·(-12)
Δ = -39
Delta is less than zero, so there is no solution for the equation

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